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Quartus电子拔河游戏VHDL代码开发板

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2-231226111401461.doc

共1个文件

名称:Quartus电子拔河游戏VHDL代码开发板

软件:Quartus

语言:VHDL

代码功能:

设计一个能进行拔河游戏的电路

电路使用15个(或9个)发光二极管表示拔河的“电子绳”,开机后只有中间一个发亮,此即拔河的中心点。

游戏甲乙双方各持一个按钮,迅速地、不断地按动产生脉冲,谁按得快,亮点向谁方向移动,每按一次,亮点移动次。

亮点移到任一方终端二极管,这一方就获胜,此时双方按钮均无作用,输出保持,只有复位后才使亮点恢复到中心。

由裁判下达比赛开始命令后,甲乙双方才能输入信号,否则输入信号无效。

数码管显示获胜者的盘数,每次比赛结束自动给获胜方加分。

FPGA代码Verilog/VHDL代码资源下载:www.hdlcode.com

本代码已在开发板验证,开发板如下,其他开发板可以修改管脚适配:开发板.jpg

演示视频:

设计文档:

1. 工程文件

2. 程序文件

3. 程序编译

4. RTL图

状态图

5. 管脚分配

6. 仿真图

部分代码展示:

LIBRARY?ieee;
???USE?ieee.std_logic_1164.all;
???USE?ieee.std_logic_unsigned.all;
--控制模块
ENTITY?bahe_ctrl?IS
???PORT?(
??????clk???????:?IN?STD_LOGIC;--标准时钟
??????reset_n????????:?IN?STD_LOGIC;--复位信号,低有效?
reset_cnt????????:?IN?STD_LOGIC;--计数复位信号,低有效?
??????shift1???????:?IN?STD_LOGIC;--选手1
??????shift2???????:?IN?STD_LOGIC;--选手2
??????led????????????:?OUT?STD_LOGIC_VECTOR(6?DOWNTO?0);--7个led
led_flash??????:?OUT?STD_LOGIC;
???win1_times?????:OUT?STD_LOGIC_VECTOR(15?DOWNTO?0);--1号获胜次数
???win2_times?????:OUT?STD_LOGIC_VECTOR(15?DOWNTO?0)--2号获胜次数
???);
END?bahe_ctrl;
ARCHITECTURE?behave?OF?bahe_ctrl?IS
???
???TYPE?State_type?IS?(s_idle,?s_start,?s_left_shift,?s_right_shift,?s_win_1,?s_win_2);??--?定义状态
???SIGNAL?state?:?State_Type;????--?创建信号
???SIGNAL?game_led??????:?STD_LOGIC_VECTOR(6?DOWNTO?0)?:=?"0001000";
SIGNAL?win1_num??????:?STD_LOGIC_VECTOR(15?DOWNTO?0)?:=?"0000000000000000";
SIGNAL?win2_num??????:?STD_LOGIC_VECTOR(15?DOWNTO?0)?:=?"0000000000000000";
???SIGNAL?cnt1?:?STD_LOGIC_VECTOR(31?DOWNTO?0)?:=?"00000000000000000000000000000000";
???SIGNAL?clk1?:?STD_LOGIC?:=?'0';
BEGIN
???PROCESS?(clk)
???BEGIN
??????IF?(clk'EVENT?AND?clk?=?'1')?THEN
?????????IF?((NOT(reset_n))?=?'1')?THEN
????????????state?<=?s_idle;
?????????ELSE
????????????CASE?state?IS
???????????????WHEN?s_idle?=>--复位状态
?????????????????????state?<=?s_start;
???????????????WHEN?s_start?=>--游戏中
??????????????????IF?(game_led?=?"1000000")?THEN
?????????????????????state?<=?s_win_1;--1号赢
??????????????????ELSIF?(game_led?=?"0000001")?THEN
?????????????????????state?<=?s_win_2;--2号赢
??????????????????ELSIF?(shift1?=?'1')?THEN
?????????????????????state?<=?s_left_shift;--led左移
??????????????????ELSIF?(shift2?=?'1')?THEN
?????????????????????state?<=?s_right_shift;--led右移
??????????????????ELSE
?????????????????????state?<=?s_start;
??????????????????END?IF;
???????????????WHEN?s_left_shift?=>--led左移
??????????????????state?<=?s_start;
???????????????WHEN?s_right_shift?=>--led右移
??????????????????state?<=?s_start;
???????????????WHEN?s_win_1?=>
??????????????????state?<=?s_win_1;--1号赢
???????????????WHEN?s_win_2?=>
??????????????????state?<=?s_win_2;--2号赢
???????????????WHEN?OTHERS?=>
????????????END?CASE;
?????????END?IF;
??????END?IF;
???END?PROCESS;
???
???
???PROCESS?(clk)
???BEGIN
??????IF?(clk'EVENT?AND?clk?=?'1')?THEN
?????????IF?((NOT(reset_n))?=?'1')?THEN--复位
????????????game_led?<=?"0001000";
?????????ELSIF?(state?=?s_left_shift)?THEN
????????????game_led?<=?(game_led(5?DOWNTO?0)?&?'0');--led左移
?????????ELSIF?(state?=?s_right_shift)?THEN
????????????game_led?<=?('0'?&?game_led(6?DOWNTO?1));--led右移
?????????END?IF;
??????END?IF;
???END?PROCESS;
???PROCESS?(clk)
???BEGIN
??????IF?(clk'EVENT?AND?clk?=?'1')?THEN
?????????IF?((NOT(reset_cnt))?=?'1')?THEN--复位
????????????win1_num?<=?"0000000000000000";
?????????ELSIF?(state?=?s_start?and?game_led?=?"1000000")?THEN----1号赢
????????????win1_num?<=win1_num+?"0000000000000001";--加1
?????????ELSE
win1_num?<=win1_num;
?????????END?IF;
??????END?IF;
???END?PROCESS;???
???PROCESS?(clk)
???BEGIN
??????IF?(clk'EVENT?AND?clk?=?'1')?THEN
?????????IF?((NOT(reset_cnt))?=?'1')?THEN--复位
????????????win2_num?<=?"0000000000000000";
?????????ELSIF?(state?=?s_start?and?game_led?=?"0000001")?THEN----2号赢
????????????win2_num?<=win2_num+?"0000000000000001";--加1
?????????ELSE
win2_num?<=win2_num;
?????????END?IF;
??????END?IF;
???END?PROCESS;
???PROCESS?(clk)
???BEGIN
??????IF?(clk'EVENT?AND?clk?=?'1')?THEN
?????????IF?(cnt1?>=?"00000000001111010000100100000000")?THEN
????????????cnt1?<=?"00000000000000000000000000000000";
????????????clk1?<=?NOT(clk1);
?????????ELSE
????????????cnt1?<=?cnt1?+?"00000000000000000000000000000001";
?????????END?IF;
??????END?IF;
???END?PROCESS;
--输出
win1_times<=win1_num;
win2_times<=win2_num;
???led?<=?game_led;
led_flash<=clk1;
END?behave;

点击链接获取代码文件:http://www.hdlcode.com/index.php?m=home&c=View&a=index&aid=418

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